Question 1035084
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Elaine has 88 coins in a purse which are all 5-cent coins and 10-cent coins. The total value of the coins are $7. 
How many of each type of coin does she have?
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Let n be the number of nickels (5-cent coins) Elain has.
Then the number of dimes (10-cent coins) is (88-n).

   n   nickels contribute 5n cents into the total.
(88-n) dimes   contribute 10*(88-n) cents into the total.

So, you have this "value" equation

5n + 10*(88-n) = 700   cents.

Simplify and solve:

5n + 880 - 10n = 700,  or

-5n = 700 - 880,

-5n = -180,

n = {{{(-180)/(-5)}}} = {{{180/5}}} = 36.

So, Elaine has 36 nickels (5-sent coins) and 88-36 = 52 dimes (10-cent coins).

<U>Check</U>. 5*36 + 10*52 = 180 + 520 = 700 cents.   Correct!
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