Question 1035051

Solve using quadratic formula. 2y^2-10y+8=0
<pre>{{{2y^2 - 10y + 8 = 0}}}
{{{2(y^2 - 5y + 4) = 2(0)}}} ------- Factoring out GCF, 2
{{{y^2 - 5y + 4 = 0}}}
Now solve this for y, using the quadratic equation formula: {{{y = (- b +- sqrt(b^2 - 4ac))/(2a)}}}, where: {{{matrix(1,4, a = 1, b = - 5, and, c = 4)}}}