Question 1035011
{{{(9a^3b^2-18a^2b^3)/(3a^2b)}}}


Factorize the numerator and cancel common occurrances of factors between numerator and denominator.


{{{(9a^2b^2(a-2b))/(3a^2b)}}}



{{{highlight(3b(a-2b))}}}




---
What here do you not understand?


---
The full set of steps:


{{{(9a^3b^2-18a^2b^3)/(3a^2b)}}}


{{{(3*3a^3b^2-2*3*3a^2b^3)/(3a^2b)}}}


{{{(3a^2b^2(3a-2*3b))/(3a^2b)}}}


{{{((3a^2b^2)/(3a^2b))(3a-2*3b)}}}


{{{((3aabb)/(3aab))(3a-2*3*b)}}}


{{{((cross(3aab)b)/(cross(3aab)))(3a-2*3*b)}}}


{{{b(3a-2*3*b)}}}


{{{b(3a-6b)}}}-----almost fully simplified but still somewhat in factored form


{{{highlight(3ab-6b^2)}}}



----
JUST PICK THE RIGHT CHOICE.  ALL THE SOLUTION STEPS ARE SHOWN FOR YOU.