Question 89219



      Factor completely:
f(x)=x^4-5x^3+6x^2

  f(x) = x^4-5x^3+6x^2
       = x^2(x^2-5x+6)
       = x^2(x^2-3x-2x+6)
       = x^2[x(x-3)-2(x-3)]
       = x^2(x-3).(x-2)