Question 1034971
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ \text{mod}\ b]


is the remainder when *[tex \Large b] divides *[tex \Large a] using integer division.  In other words,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ qb\ +\ r]


Where *[tex \Large q] is the quotient when *[tex \Large b] divides *[tex \Large a] and *[tex \Large r] is the remainder, and *[tex \Large a\ \text{mod}\ b\ =\ r]


The additive inverse of *[tex \Large a] is *[tex \Large -a] for all real numbers *[tex \Large a]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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