Question 1034930
X is 5 years older than Y.<pre>X = Y+5</pre>Z is 6 years older than X.<pre>Z = X+6</pre>...the sum of their ages is 31...<pre>X+Y+Z = 31

First substitute (Y+5) for X in Z = X+6
and simplify.

Then substitute (Y+5) for X and Z = (what you got)
into X+Y+Z = 31 and solve for Y.

Then substitute that value for Y in X = Y+5 to
find X.

Then substitute what you got for X in Z = X+6
to find Z.

I won't tell you the answers but one of them is
twice as old as another of them.

Edwin</pre>