Question 1034870
In simultaneous equation, using substitution method, solve 
3x + 3y = 10
2x - y = 2 
:
Rearrange the 2nd equation for substitution
subtract 2x from both sides
-y = -2x + 2
multiply by -1
y = 2x - 2
:
Replace y with (2x-2) in the 1st equation
3x + 3(2x - 2) = 10
3x + 6x - 6 = 10
9x = 10 + 6
9x = 16
x = 16/9
:
Find y
y = 2(16/9) - 2
y = (32/9) - (18/9)
y = (14/9)
:
Solution
x = 16/9
y = 14/9
:
:
:
Check this on your calc in the 1st equation
3(16/9) + 3(14/9) =