Question 1032674
Okay, using
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
we have
a = 5
b = 10
c = -4
Now plug in and get
{{{k = (-10 +- sqrt( 10^2-4*5*(-4) ))/(2*5) }}}
{{{k = (-10 +- sqrt(180))/10}}}
{{{k = (-10 +- 6*sqrt(5))/10}}}
{{{k = (-5 +- 3*sqrt(5))/5}}}
That is the exact solution...use your calculator if you need numbers...