Question 89248


    divide: p^2+4p-5/p^2+7p+10 × p+4/p-1

    Factorise p^2+4p-5 = p^2+5p-p-5 = p(p+5)-1(p+5) = (p+5).(p-1)
              
               p^2+7p+10 = p^2+5p+2p+10 = p(p+5)+2(p+5) = (p+5).(p+2)

    Therefore p^2+4p-5/p^2+7p+10 x p+4/p-1 = (p+5).(p-1).(p+4)/(p+5).(p+2).(p-1)
                                           = (p+4)/(p+2)