<PRE><B>Question 1034791</B>
You have a right triangle where one leg is 3 more than triple the other leg and the hypotenuse is one unit longer than the longest leg. What are the length of the three sides? solve using polynomials 
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leg:: x
other leg:: 3x+3
hypot:: 3x+4
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(3x+4)^2 = x^2 + (3x+3)^2
9x^2 + 24x + 16 = x^2 + 9x^2 + 18x + 9
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6x = -3
x = -1/2 (that is impossible)
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What happened?
The sum of the leg lengths is x + 3x+3 = 4x+3
And 4x + 3 is greater than the length of the hypotenuse which is 3x+3
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You cannot have a triangle where the sum of the legs exceeds the
length of the 3rd side.
Cheers,
Stan H.</PRE>