Question 1034543
a)  It reaches a maximum height when the velocity is zero.
v(t) = 0 = h'(t) = -32t + 32 ==> t=1 second
b)  At that time, h(1) = -16 + 32 + 28 = 44 feet
c)  To find this, we let h(t) = 0 and solve for t...thus
-16t^2 + 32t + 28 = 0
-4t^2 + 8t + 7 = 0
4t^2 - 8t - 7 = 0
and 
t = 2.66 seconds