Question 89362

   Solve by using the quadratic formula. 
5x^2 + x = 3

        5x^2+x-3 = 0   compare with the std form ax^2+bx+c= 0 

      we get a= 5, b = 1 and c= -3
      the  std formula is {{{x = (-b+-sqrt(b^2-4ac))/2*a*}}}

              x = (-1+-sqrt(1^2-4*5*-3)/2*5
                = {-1+-sqrt(1+60)}/10
                = {-1+-sqrt(61)}/10