Question 1034664
Well, this is kind of a tricky elimination problem, but here goes...from
4x-3y=10 
2x-5=3/2y
let us multiply the bottom equation by two and subtract it from the top one...
4x - 3y = 10
-(4x - 10 = 3/y)
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-3y + 10 = 10 - 3/y
Now subtract 10
-3y = -3/y
Now divide by -3
y = 1/y
y^2 = 1
y = 1 or y = -1
If y = 1, we have
4x - 3(1) = 10
4x = 13
x = 13/4
If y = -1, we have
4x - 3(-1) = 10
4x + 3 = 10
4x = 7
x = 7/4
so it looks like there are two solutions...
(13/4, 1) and
(7/4, -1)
You can check...