Question 89343


   Find the solution set for
x/x-1 - 1/x+1 = 2/x^2-1

 L.C.M.   of x-1   & x+1 is x^2-1

   x(x+1)-1(x-1)/x^2-1 = 2/x^2-1

    x^2+x-x+1 = 2   (cancel  x^2-1  on both sides)

     x^2+1-2 = 0
       x^2-1 = 0
      (x+1) (x-1) = 0 

        x+1 = 0   or x = -1

        x-1 = 0   or x= 1  therefore  solution set for the given expression 

           is x = +1  or -1