Question 1034532
.
I am working on solving quadratic equations with substitutions. 
(y-10/y)^2-6(y'10/y)-27=0
I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from what I got. 
Now I am having difficulty inputting those answers back into the equation to solve for y. y-10/y=9 or y-10/y=-3. 
Any help is greatly appreciated. Thank you 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
{{{(y-10)/y}}} = 9  --->  multiply both sides by y  --->

y - 10 = 9y,

-10 = 9y - y,

-10 = 8y,

y = {{{-10/8}}}.

---------------------


{{{(y-10)/y}}} = -3  --->  multiply both sides by y  --->

y - 10 = -3y,

-10 = -3y - y,

-10 = -4y,

y = {{{10/4}}}.
</pre>