Question 1034454
Let g(s) = (square root of s )(4-s^2), find g's
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If you mean the 1st derivative, g'(s):
g(s) = s^(0.5)*(4-s^2)
g's = {{{0.5*s^(-0.5)*(4-s^2) + s^(0.5)*(-2s)}}}  -- product rule
= {{{(4-s^2)/(2sqrt(s)) - 2s*sqrt(s)}}}