Question 1030135
Say the width of your pool is w; the length is then equivalent to 2w. The width and length of your walkway are w+4 (2 feet are added to each side, thus adding 4 to the total), and 2w+4. Thus the area is:
(w+4)(2w+4)=1056
2w^2+12w+16=1056
2w^2+12w-1040=0
w^2+6w-520=0
(w+26)(w-20)=0
w=-26,20
Our only real solution is width=20, length=40!!!!!!!!