<PRE><B>Question 1032796</B>
Well, given the equation
s(t) = -16t^2 + 96t + 96
we can find the height at any time t...we can also find t for any height s(t)...thus if we want to know when it hits the ground, s(t) = 0...so we have
0 = -16t^2 + 96t + 96
0 = -t^2 + 6t + 6
t^2 - 6t - 6 = 0
so that, using the quadratic formula we find, 
 {{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
and
t = 6.9 seconds (to the nearest tenth)</PRE>