Question 1034350
{{{dv/dt=10* (m^3/s)}}} What is {{{dh/dt}}} when h=10m. Since {{{V=pi*r^2*h}}}and
{{{dV/dt=pi*r^2*(dh/dt)}}}, since {{{dV/dt=10}}} we get {{{10=pi*100*(dh/dt)}}}
and {{{dh/dt=1/(10*pi)}}}. The rate of change of the height is {{{1/(10*pi)}}}.