Question 1034350
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A cylindrical tank, with the circular base on the ground, of radius 10 meters, and a height of 20 meters, 
is filling with water at a rate of 10 cubic meters per second. 
What is the rate of change of the height of the water when the height is 10 meters?
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Simply divide the rate of 10 {{{m^3}}} by the area of the cross-section of the cylindrical tank:

{{{dh/dt}}} = {{{10/(pi*r^2)}}} = {{{10/(3.14*10^2)}}}.

The height of the tank is an excessive data in this problem. 
It is not relevant neither the solution nor the answer.
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