Question 12876
This is similar to graphing Linear Equations of the form y = mx + b. There are only two differences, first, after you plot 2 points, you need to determine weather the line is dashed or solid, then where to shade. But graphing is the same.
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The first thing you need to do is plot your y-intercept ( where the line crosses the y-axis ) this would be at +3 since the equation is y > 2x + 3.
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Now we know the slope is 2 or 2/1, so using Rise/Run, you are going to start at your y-intercept, move up two spaces and right 1, so you should now be at the point (1,5)
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Determining if the line is shaded or not just takes a quick glance at the sign of the equation. If the sign is just Greater Than or Less Than the line will be dashed, however, if it is a Greater Than or Equal To, or Less Than or Equal To it will have to be solid.
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Now as for the shading part, what you want to do is choose a point that is NOT on your line, in most cases ( 0,0 ) is the best choice because its easy, but this will ONLY work if the line does not pass through this point, for this problem our line does  NOT pass through ( 0,0 ) so we are going to choose that point.
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Now, Substitute the x value for x and the y value for y, and simplify ( see below)
{{{ y > 2x + 3 }}} Substitute
{{{ 0 > 2(0) + 3 }}} Simplfy each side of the equation
{{{ 0 > 3 }}}
Now you need to ask your self a question, does this make sense? Is 0 > 3, of course not, so you need to shade on the side of the line that does NOT include (0,0) in this case you would shade ABOVE the line...
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If the statement made sense, say 0 < 3, then you would want to shade BELOW the line, or shade towards the point that gave you the true solution.

Hope this helps. Mr. C