<PRE><B>Question 1034083</B>
 The formula h=-16t^2+vt gives the height h in meters of an object after t second, when it is shot upward into the air with an initial velocity v in meters per second.
 After how many seconds will the object hit the ground if it is shot with a velocity of 19.6 meters per second?
  When the object hits the ground the h=0, therefore
-16t^2 + 19.6t = 0
Divide by -t
16t - 19.6 = 0
16t = 19.6
t = 19.6/16
t = 1.225 sec to hit the ground
:
The h is 58.8 meters high
The object never gets that high as you can see
{{{ graph( 300, 200, -1, 3, -4, 10, -16x^2+19.6x) }}}
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