Question 1034084
All we do is substitute the values 1 thru 5 in for n...we get
{{{a[1] = (-1)^1*(3/2)^1 = -3/2}}}
{{{a[2] = (-1)^2*(3/2)^2 = 9/4}}}
{{{a[3] = (-1)^3*(3/2)^3 = -27/8}}}
etc.