Question 1034007
L1 and r1 are the reference loudness and reference distance, then
:
L2 = L1 - | 20 * log (r1 / r2) |
:
L1 = 110 and r1 = 100
:
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L2 = 110 - | 20 * log (100 / 50) | = 116.02
:
at 50 feet the loudness reading is 116.02 dB
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:
r2 = r1 * 10^( |L1 - L2| / 20)
:
r2 = 100 * 10^( |110 - 90| / 20) = 1000
:
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r2 is 1000 feet
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