Question 1034029
If we find the slope of
2y+3x=6
we can do that by solving for y...
2y = -3x + 6
y = (-3/2)x + 3
Since we want a perpendicular line, the slope we need is 2/3.
Now plug in to y = mx + b to find b...
5 = (2/3)(6) + b
5 = 4 + b
b = 1
so the line we want is
y = (2/3)x + 1