Question 1033951
If you meant {{{4^(2x+7)=32^(x+3)}}}, then

 {{{2^(2(2x+7))=2^(5(x+3))}}},

==> 2(2x+7) = 5(x+3) ==> 4x + 14 = 5x + 15 ==> x = -1.