Question 1033949
Area of sphere,  {{{4pi*r^2}}}
but for diameter {{{d=2r}}}, area is  {{{4pi(2d)^2=highlight(16pi*d^2)}}}.



Question asks to computer   {{{-16pi*5^2+16pi*20^2}}}.
{{{16pi(400-25)}}}
{{{375*16pi}}}
Finish in any way you want.