Question 1033853
Quadrilateral LOVE is a parallelogram, with sides LO and VE having slope 1/3 and sides OV and LE having slope 3.  
Also, {{{abs(OL) = sqrt(10) = abs(OV)}}} after using the distance formula.

It is enough to show that one of the interior angles is not a right angle.

Angle OVE {{{theta}}} is evaluated as follows:  {{{tan(theta) = (m[OV] - m[VE])/(1+m[OV]*m[VE]) = (3-1/3)/(1+3*(1/3)) = (8/3)/2 = 4/3}}}

==> {{{theta = tan^-1(4/3) <>pi/2}}}.

Therefore LOVE is a rhombus but not a square.