Question 1033948
From the given, y = 1-x.  ==> {{{ 2x^2 -4x = 1-x + 1 }}} <==> {{{ 2x^2 -3x - 2=0}}} <==> (2x+1)(x-2) = 0  ==> x = -1/2, 2.

When x = -1/2, y = 1--1/2 = 3/2.
When x = 2, y = 1-2 = -1.

Therefore the solutions to the system are (-1/2, 3/2) and (2,-1).