Question 1033939
the concentration of the 1st solution is:
{{{ 15 / ( 15 + 45 ) = 15/60 }}}
{{{ 15/60 = .25 }}}
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Let {{{ x }}} = ml of HCL in the 2nd solution
{{{ x / ( x + 132 ) = .25 }}}
{{{ x = .25*( x + 132 ) }}}
{{{ x = .25x + 33 }}}
{{{ .75x = 33 }}}
{{{ x = 44 }}}
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The 2nd solution must contain 44 ml of HCL
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check:
{{{ x / ( x + 132 ) = .25 }}}
{{{ 44 / ( 44 + 132 ) = .25 }}}
{{{ 44 / 176 = .25 }}}
{{{ 44 = .25*176 }}}
{{{ 44 = 44 }}}
OK