Question 1033882
.
{{{y+2x=6}}} 
{{{y=6-2x}}}
.
{{{y=x^2-6x+1}}}
{{{6-2x=x^2-6x+1}}}
{{{6=x^2-4x+1}}}
{{{0=x^2-4x-5}}}
{{{0=(x-5)(x+1)}}}
{{{x-5=0}}} {{{OR}}} {{{x+1=0}}}
{{{x=5}}} {{{OR}}} {{{x=-1}}}
.
For x=5:
y+2x=6
y+2(5)=6
y+10=6
y=-4
.
CHECK:
{{{y=x^2-6x+1}}}
{{{-4=(5)^2-6(5)+1}}}
{{{-4=25-30+1}}}
{{{-4=-5+1}}}
{{{-4=-4}}}
.
For x=-1:
y+2x=6
y+2(-1)=6
y-2=6
y=8
.
CHECK:
{{{y=x^2-6x+1}}}
{{{8=(-1)^2-6(-1)+1}}}
{{{8=1+6+1}}}
{{{8=8}}}
.
ANSWERS: (5,-4) and (-1,8)
.