Question 1033818
To find the position, integrate the velocity.
{{{v(t)=1-2/t}}}
So then,
{{{x(t)=int((v(t)),dt)}}}
{{{x(t)=int((1-2/t),dt)}}}
{{{x(t)=t-ln(t)+C}}}
So when {{{t=1}}},
{{{1-ln(1)+C=10}}}
{{{1+C=10}}}
{{{C=9}}}
{{{highlight(x(t)=t-ln(t)+9)}}}
.
.
When {{{t->infinity}}},
{{{v(t)=1-0}}}
{{{v(t)=1}}}