Question 1033712
The bus is approaching the town and the car is
leaving the town
Let {{{ d }}} = distance in miles each one has traveled
Since they are traveling at the same rate, I can say
that the bus's distance from the town is {{{ 13 - d }}} and
the cars distance from town is {{{ d }}} at time {{{ t }}} in hours
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The car's equation:
{{{ d = 80t }}}
The problem is telling me that:
{{{ 13 - d = 2d }}}
{{{ 3d = 13 }}}
{{{ d = 13/3 }}}
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{{{ d = 80t }}}
{{{ 13/3 = 80t }}}
{{{ t = 13/240  }}}
In minutes:
{{{ t = ( 13/240 )*60 }}}
{{{ t = 13/4 }}}
{{{ t = 3.25 }}} min
After 3.25 min, the bus's distance from 
town will be twice the car's distance
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check:
In {{{ 13/240 }}} hrs, the car travels
{{{ d = 80*(13/240 ) }}}
{{{ d = 13/3 }}} mi
and the bus has traveled the same distance.
The bus is {{{ 13 - 13/3 = (2/3)*(13) }}}
miles from town
So, the bus is twice as far from town as the car
Hope you can follow this and hope I'm right