Question 1033712
Try to draw a picture and form a data table.

<pre>
            rate     time        distance moved
BUS         80         t           d               80t=d
CAR         80         t           d               80t=d
</pre>

t is used for both because this is the same time quantity.


Bus distance from the town becomes 80t+13.
Car distance from the town becomes 80t.
Review all of this a few times with concentration so you understand.



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When that makes sense, look at the question.
How much time t for the bus to be twice the car, FROM THE TOWN?


{{{80t+13=2(80t)}}}
Again, review all of this including this equation so that it also makes sense for you.


You want to solve for t, in this last equation.
{{{80t+13=2*80t}}}
{{{80t+13-80t=2*80t-80t}}}
{{{13=80t}}}
{{{13/80=t}}}------this is fraction of an hour, so you can convert to minutes if you want.