Question 1033689
x^2 + y^2 - 2x + 8y + 8 = 0
----------------
Rearrange::
x^2 - 2x   + y^2 + 8y  = -8
------
Complete the square on the x-terms and on the y-terms ::
---------------------
x^2 - 2x +1 + y^2 + 8y + 16 = -8 + 1 + 16
-------------------------------------------
(x-1)^2 + (y+4)^2 = 9
---------
Center:: (1,-4)
radius:: sqrt(9) = 3
----------------------
Cheers,
Stan H.
--------------