Question 1033654
solve the equation {{{ 3^2x = 2^x-1.}}} round your answer to 3 decimal places 
please show me how to work this out because I am stuck

also the exponent for 3 is 2x
the exponent for 2 is x-1
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{{{ 3^(2x) = 2^(x-1)}}}
2x*log(3) = (x-1)*log(2) = x*log(2) - log(2)
2x*log(3) - x*log(2) = -log(2)
x*(2log(3) - log(2)) = -log(2)
x = log(2)/(log(2 - log(9))
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x =~ -0.460845