Question 1033524
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An environmental organization has 19 members. Each member will be placed on exactly 1 of 4 teams. 
Each team will work on a different issue. The first team has 3 members, the second has 5, the third has 7, and the fourth has 4. 
In how many ways can these teams be formed? 
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1.       You can select 3 members from 19 members to the 1-st team by {{{C[19]^3}}} ways.

2.  Then you can select 5 members from remaining 19-3 = 16 members to the 2-nd team by {{{C[16]^5}}} ways.

3.  Then you can select 7 members from remaining 16-5 = 11 members to the 3-rd team by {{{C[11]^7}}} ways.

4.  Then you can select 4 members from remaining 11-7 = 4 members to the 4-th team by {{{C[4]^4}}} = 1 ways.

    (Actually, you just have no choice at this last step).


5.  In total, you have  {{{C[19]^3}}} * {{{C[16]^5}}} * {{{C[11]^7}}}  ways to form yours teams. 


Thus I just explained the methodology to you, and I leave to you making the calculations.


Last notice:  the quantities  {{{C[n]^k}}}  are the numbers of combinations of "n" things taken "k" at a time.

See the lesson  <A HREF=https://www.algebra.com/algebra/homework/Permutations/Introduction-to-Combinations-.lesson>Introduction to Combinations</A>  in this site.
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