Question 89174
Solve for x by completing the square:
{{{x^2-16x+63 = 0}}} First, subtract 63 from both sides.
{{{x^2-16x = -63}}} Now complete the square in the x-terms by adding the square of half the x-coefficient {{{(-16/2)^2 = 64}}} to both sides.
{{{x^2-16x+64 = 64-63}}} Simplify.
{{{x^2-16x+64 = 1}}} Factor the left side.
{{{(x-8)^2 = 1}}} Take the square root of both sides.
{{{x-8 = 1}}} or {{{x-8 = -1}}} 
{{{x = 8+1}}} or {{{x = 8-1}}}
{{{x = 9}}} or {{{x = 7}}}