Question 1033372
.
Solve by substitution method:
(x+2)/5 = (y-1)/2 
and
(x-1)/2 - (2y+1)/3 = 1

How to do this? Please have steps
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{{{(x+2)/5}}} = {{{(y-1)/2 }}},           (1)
{{{(x-1)/2}}} - {{{(2y+1)/3}}} = {{{1}}}.    (2)
 
From (1), x + 2 = {{{(5(y-1))/2}}}.

Hence, x - 1 = {{{(5(y-1))/2 - 3}}} = {{{(5y - 5 - 6)/2}}} = {{{(5y-11)/2}}}.
Now, substitute this expression for (x-1) into equation (2). You will get

{{{(5y-11)/4}}} - {{{(2y+1)/3}}} = {{{1}}}.

It is a single equation for y.

Can you solve it yourself?

I think from this point you can complete this assignment.
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