Question 1033368
y = log_2 (2x)
2^y=2x
(2^y)/2=2^(y-1)
2^(y-1)=x
y = log_4 (x)
4^y=x
2^2y=x
(2^2y)=4^y
2^2y=2^(y-1)
y-1=2y
y=-1
4^-1=1/4
(1/4,-1)