Question 1032915
P(HH) = P(TT) = x
P(HT) = P(TH) = x/7 (since P(HH) = 7*P(HT))


Since HH, TT, HT, TH are disjoint and one of these outcomes must occur, the sum of their probabilities is 1. Hence x + x + (x/7) + (x/7) = 1, or x = 7/16.


a) P(HH) = x = 7/16
b) P(A) = 1 - P(TT) = 9/16
c) P(B) = P(HH) + P(TT) = 7/8