Question 1033235
*[illustration xs5.JPG].
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From the diagram,
{{{R[1]=S/2}}}
and
{{{(S/2)^2+(S/2)^2=R[2]^2}}}
{{{S^2/4+S^2/4=R[2]^2}}}
{{{S^2/2=R[2]^2}}}
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In terms of area,
{{{A[1]=pi*R[1]^2}}}
{{{A[1]=pi*(S/2)^2}}}
{{{A[1]=pi*(S^2/4)}}}
{{{A[1]=(pi/4)S^2}}}
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{{{A[2]=pi*R[2]^2}}}
{{{A[2]=pi*(S^2/2)}}}
{{{A[2]=(pi/2)S^2}}}
So then,
{{{A[2]=2A[1]}}}
{{{A[2]/A[1]=2}}}
{{{highlight(A[1]/A[2]=1/2)}}}