<PRE><B>Question 1033322</B>
 Find the quadratic function y=ax2+bx+c whose graph passes through the given points.
&amp;#8203;(3,&amp;#8722;11&amp;#8203;), &amp;#8203;(&amp;#8722;2&amp;#8203;,&amp;#8722;16&amp;#8203;), &amp;#8203;(1,&amp;#8722;1&amp;#8203;) 
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(3,-11) gives:: 9a + 3b + c = -11
(-2,-16) gives: 4a - 2b + c = -16
(1,-1) gives::    a + b + c = -1
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Use any method you know to solve the system for a,b,c.
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a = -2 ; b = 3; c = -2
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Equation:
y = -x^2 + 3x -2
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Cheers,
Stan H.
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