Question 89126
{{{x^2=-5x+11}}}
First, re-write the equation in standard form. Standard form is:
{{{ax^2+bx+c=0}}}
So, for your problem the standard form is:
{{{x^2+5x-11=0}}}
The quadratic equation is:
{{{x=(-b+-sqrt(b^2-4ac))/2a}}}
In your case, a=1, b=5, and c=-11
So plug that in to the quadratic equation:
{{{x=(-5+-sqrt(5^2-(4)(1)(-11)))/(2*1)}}}
Simplify:
{{{x=(-5+-sqrt(25+44))/2}}}
{{{highlight(x=(-5+-sqrt(69))/2)}}}
If you want to simplify this more, just plug the numbers into your calculator. But getting to this point is the important thing!
Good Luck,
tutor_paul@yahoo.com