Question 1033182
Use the constraint equations to find the feasible region and the vertices.
{{{graph(300,300,-2,10,-2,10,2x+3y<=16)}}}
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{{{graph(300,300,-2,10,-2,10,3x+y<=10)}}}
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{{{graph(300,300,-2,10,-2,10,(16-2x)/3,(10-3x))}}}
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There are four vertices to test.
({{{0}}},{{{0}}})
({{{0}}},{{{16/3}}})
({{{2}}},{{{4}}})
({{{10/3}}},{{{0}}})
I'll do one, you do the rest the same way.
({{{0}}},{{{0}}}): {{{R=12(0)+15(0)=0}}} Obviously not the solution.
Check the other three vertices the same way.