Question 1033249
q = d+4
n = 3d
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.05n+.10d+.25q = 4.50 Substitute for q and n:
.05(3d)+.10d+.25(d+4)= 4.50
.15d+.10d+.25d+1 = 4.50
.50d = 3.50
d = 7
q = 7+4 = 11
n = 3(7) = 21
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Check:
d = 7(.10) = .70
q = 11(.25)= 2.75
n = 21(.05)= 1.05
. . . . . . -------
Total: . . . 4.50 Correct
John