Question 1033169
{{{sin(theta)=x/1}}}
{{{sin^(-1)(x)=theta}}}
So then,
{{{sin^2(theta)+cos^2(theta)=1}}}
{{{x^2+cos^2(theta)=1}}}
{{{cos^2(theta)=1-x^2}}}
{{{cos(theta)=sqrt(1-x^2)}}}
So then,
{{{cos(sin^(-1)(x))=cos(theta)}}}
{{{cos(sin^(-1)(x))=sqrt(1-x^2)}}}