<PRE><B>Question 1033112</B>
Vehicle A and B, moving at a constant velocities, are 8km apart at the starting time of 3:40pm.
 If after 40 mins, Vehicle B overtakes A, at what time will they be 10 km apart? 
:
We are dealing with their relative speed here.
40 min = 2/3 hr
speed = dist/time
We know from the given information that the difference in their velocities is:
{{{8/(2/3)}}} = 12 km/hr the relative speed to each other
:
How long will it take to travel 10 km at 12 km/hr?
{{{10/12}}} = {{{5/6}}} hr which is {{{5/6}}} * 60 = 50 min
:
Travel time from 3:40. 50 min + 40 min = 90 min from 3:40: 5:10 pm
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