Question 1033079
{{{dV = pi*x^2dy = pi*(1-y^2)^2dy}}}

==> {{{int(1,dV, y=-1, y=1) = pi*int(x^2,dy,-1,1) = 2*pi*int((1-y^2)^2,dy,0,1) = 2*pi*int((1-2y^2+y^4),dy,0,1)}}}

= {{{2*pi*(y - (2/3)y^3 + y^5/5)[0]^1 = 2*pi*(1-2/3 + 1/5)}}} 

= {{{(16*pi)/15}}}