Question 1033063
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The quadratic formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


Where *[tex \Large a,\,b,\,c] are the coefficients of the equation.  Just plug in the numbers and do the arithmetic.  Simplify the radical if you have to submit an exact answer.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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